Free Essay

In: Other Topics

Submitted By chinkee24m

Words 1180

Pages 5

Words 1180

Pages 5

Scenario :

A family is looking for the best option for moving the family’s belongings into a new home.

Moving company A charges its customers a flat rate per mile. Moving company B charges it customers a fixed amount for a certain number of miles and then a fixed rate per mile for any miles over the set amount. Determine which company would best serve the needs o the family.

A. Develop a story problem using the real-world scenario you have selected from the four provided above by doing the following:

1. Develop a cost comparison problem that can be solved according to the task instructions that follow by supplementing your chosen scenario with additional information.

A Family is moving from San Jose downtown to Tracy Downtown. The net distance from San Jose location to Tracy is 95 miles. Family has requested the moving quotes from two different Companies. Company A charges Flat $15 per mile and company B charges $800 for first 40 miles and then $10 per miles for remaining distance.

X = Distance from San Jose to Trace = 95 Miles

Company A charges flat $30 per mile.

Company A charges = Ra = 15(X) Company B charges = Rb = 800 + (X – 40) 10

2. Explain all needs (e.g., financial, non-financial, situational) of the hypothetical consumer.

Consumer needs:-

Financial

• Economical for entire cost of move

• Consumer wants insurance coverage on all moving items.

• Moving supplies should be provided by moving company.

• No extra charges if move require moving items from and to second floor. Non-financial

• Good reference from past customers utilized companies’ services.

• Company provides more man power during loading and un-loading. Situational

• Family wants to move on next week Friday afternoon.

3. Discuss two cost options that are being considered.

First cost option is flat rate which depends distance of move. Which indicate the cost is directly proportional to distance. Second cost option is also directly proportional to distance after first 40 miles. Company B Charges initial charge of 800 for first 40 miles.

B. Analyze the cost of each option algebraically by doing the following:

1. Develop an algebraic equation(s) with clearly defined variables to represent the cost of each option. X = Distance in Miles

Ra=Company A charge

Rb=Company B charge

Ra = 15(X)

Rb = 800 + (X – 40) 10

2. Explain the reasoning process used to translate the written description of each cost option into algebraic equations.

Company A charges (Ra) depends on distance(X). Company A charges flat rate $15 per mile. The charge will be multiple of distance(X) and flat per mile rate cost ($15).

Ra = 15(X)

Company B charges (Rb) depends on initial charge and distance(X -40). Company B charges initial charges for first 40 miles are $800. The charge will be sum of initial charges and the multiple of remaining distance (X -40) and rate for rest of distance per mile cost ($10).

Rb = 800 + (X – 40)10

3. Solve the system of equations algebraically to determine where the two cost options are equivalent, showing all work.

a. Explain each step used to solve the system of equations. Include the following in your explanation:

• All mathematical operations used to solve the system of equations

• The solution(s) of the system of equations in ordered-pair notation

X = Distance in Miles

Ra=Company A charge

Rb=Company B charge

Ra = 15(X)

Rb = 800 + (X – 40) 10

Two cost options are equivalent represent by Ra=Rb

Ra=Rb

15(X) = 800 + (X – 40) 10 15x =800+10(x) – 400 15x – 10x =800 – 400 5X = 400 X = 400/5 X = 80

Ra = 15(X) Ra = 15(80) Ra = 1200

(80,1200)

Rb = 800 + ( X – 40) 10 Rb = 800 + ( 80 – 40)10 Rb = 800 + 400 Rb = 1200

(80,1200)

Both cost option would be equivalent if distance(X) is 80 miles.

C. Depict the real-world problem on a single graph, within a spreadsheet application using integrated graphing tools (e.g., Microsoft Excel, OpenOffice Calc, LibreOffice Calc).

Include the following details in your graphical representation of the real-world problem:

• Label each axis of the coordinate plane with descriptive labels.

• Label all graphical solution(s) of the system of equations as “solution” and include the ordered pair.

• In a legend, indicate which cost option corresponds with each line.

• Save and submit your spreadsheet as an *.xls, *.xlsx, or *.ods file.

XLS file uploaded in TaskStream

D. Discuss a decision-making process that is based on both mathematical reasoning and non-financial, or situational, considerations. Your discussion should include the following:

• How financial information gleaned from your algebraic and graphical analyses can be used to determine the conditions for choosing cost option A over cost option B and vice versa

• How non-financial, or situational, considerations can impact the decision-making

Process

Algebraic and graphical analyses help determine the financially economical viable solution from two cost options. Consumer wants insurance coverage on all moving items. Insurance will protect customer against damages during move. The moving supply can cost consumer if that’s not provided by moving company. The moving company should not charge extra for moving items to higher floors. Both companies are in equivalent with above financial cost. The only remaining financial deciding factor is actual cost charge by moving company for move. The company B would be financially viable to move in given situation as move was greater than equivalent point 80 miles. The distance in given case is 95 miles.

Consumer should select company B for their move.

X=95

Ra = (15)X

Rb= 800 + ( X – 40) 10

Company A Charges

Ra = 15(X)

Ra = 15(95)

Ra=1425

Company B Charges

Rb = 800 + (X – 40) 10

Rb = 800 + (95 – 40)10

Rb = 800 + (55)10

Rb = 800 + 550

Rb = 1350

• How non-financial, or situational, considerations can impact the decision-making

Process

Non-financial

• Good reference from past customers utilized companies’ services.

• Company provides more man power during loading and un-loading. Situational

• Family wants to move on next week Friday afternoon.

Above non-financial and situational factors can impact the decision-making process. These factors can impact the selection of company. The good reference of companies give some comfort and confident to consumer to make decision. If company provides more man power during loading and un-loading items to truck, that will seed-up the processes and reduce the total move time.

The situational factor can make the big impact on decision-making. If company resources are not available to move on requested schedule time by consumer, than consumer have to search for moving company which can provide the services at consumer preferred schedule.

1. Discuss a final recommendation that states the option that most closely meets the consumer’s financial needs and non-financial considerations.

The Company B and Company B satisfy the consumer’s non-financial and situational consideration. The decision is finally depends on financial factor. The Company B is financially viable for consumer’s move.

Consumer should consider Company B for moving they items from San Jose downtown to Tracy downtown.…...

Free Essay

...Running Head: QLT1 Task 1 Rev 1 QLT1 Task 1 Rev 1 QLT1 Task 1 Mary is going away to college. In order to stay in touch with her family and friends she needs to get a cell phone with a calling plan. At this time Mary isn’t sure what her monthly phone usage is going to be. After consulting with her college friends, she estimates her usage will be between 200 and 900 minutes per month. A local phone company offers two basic calling plans: Plan A. offers a package consisting of monthly charge of $50.00 and $0.10 for each minute. Plan B. offer is a monthly fee of $15.00 and $0.18 per minute. The phone company charges for actual time used for both plans, so if Mary used .75 Min for talk time she would pay for actual time used [(.75) x per minute rate] Plan A The cost of plan (Y) X= phone usage in minutes (this is our variable) Y=50 + 0.10(x). The cost of plan A (Y) is $50 base charge plus $.10 per each minute (x) represented in a linear equation. Plan B X= phone usage in minutes (this is our variable) Y=15 + .18(x). The cost of plan B (Y) is $15 base charge plus $.18 per each minute (x) represented in a linear equation. 1. Which plan would offer greater savings if Mary’s monthly phone usage was 200 min? Plan A Cost of phone plan after using 200 minutes. Y=50 + .10(x) X 200 Y=50 + .10(200) Y=50 + 20 Y=70 Plan A would cost Mary $70 per month after 200 minutes usage Plan B Cost of phone plan after using 200......

Words: 659 - Pages: 3

Free Essay

...Part A: A couple is comparing two daycares to determine the best option for their 1 year old son. A home-based daycare charges a flat rate of $5 per hour. A center-based daycare charges a fixed rate of $185 per week, providing 40 hours of childcare. Above 40 hours, the center-based daycare then charges a fixed rate of $8 per hour. The couple determines that the driving distance to each daycare is the same, thus driving expenses do not need to be considered. The couple will require 50 hours of childcare per week and are looking for the cheapest daycare, as they are soon expecting their second child. Part B: 1. “y” represents total cost per week in dollars “x” represents hours Home based daycare: y=5x Center based daycare: y=185+8(x-40), x≥40 hours 2. For the home based daycare, they charge a flat rate of $5 per hour. Thus the couple can calculate their cost by multiplying $5 by the number of hours they need for childcare each week. For the center based daycare, the couple can calculate their weekly cost by adding the $185 fixed rate to the cost of any additional hours needed after 40. Thus, if they are going over 40 hours, they would subtract 40 hours from the total number of hours needed and multiply that by the $8 the center charges for each additional hour. 3. y=5x y=185+8(x-40) y=185+8(x-40) 5x=185+8x-320 5x=-135+8x 5x-8x=-135+8x-8x -3x=-135 -3 -3 x=45 y=5x y=5(45) y=225 Thus, both the center based and the home......

Words: 495 - Pages: 2

Free Essay

...QLT1 Task 5 A. Create a story problem using one of the above real-world scenarios as a basis, including realistic numeric values, by doing the following: 1. Describe the real-world problem. I was looking into phone plans and stumbled upon T-Mobile, and I decided that I needed a cell-phone and took a look at the plans. T-mobile had one plan that was 50 dollars a month and is unlimited talk, text and web, T-Mobile also has a plan for 30 dollars a month for 1,500 talk and text minutes. After you go through your allotted 1,500 talk and text time was up, the cost skyrockets up to 10 cents a minute. 10 cents a minute comes out to 6.00 per hour, I thought in my head. I decided that instead of jumping into a decision about phone plans, that I should first go home and do the math. I wanted to figure out which plan was going to be the most cost effective, and which plan would suite my needs the best. 2. Explain all needs (e.g., financial, non-financial, situational) of the hypothetical consumer. The needs include many different factors: • The first and most important factor how much do you use your phone? The breaking point on the problem today is 200 talk or text above the 1500 minute plan and I will be paying less up front but more on the back end which is no good. If I chose the 1500 minute plan, I will not want to be going over the 1500 minutes as then the cost would go up to 10 cents a minute or 6.00 per hour. • Is this replacing a work or office phone? ......

Words: 1158 - Pages: 5

Free Essay

...x 0 45 30 Y = (-2/3)x + 30 30 0 10 Y intercept: (0,30) Y = -2/3(x) + 30 Y = 0 + 30 Y= 0 X intercept: (45,0) 0 = -2/3 (x) + 5 0 – 30 = -2/3 (x) +30 -30 -30 = -2/3 x 2/3(x) = 30 X = 30 ● 3/2 X = 45 Height of the beam 30 ft. away from the face of building is 10 ft. Y = -2/3 (x) + 30 Y = -2/3 30 + 30 Y = -20 + 30 Y = 10 Y represents the height above the ground in feet. 35 Y intercept (0, 30) 30 25 The graph depicts a visual representation of the path of the laser beam using only quadrant I. Quadrants ll, lll, and lV are not needed to show the direction of the laser beam. Y = (-2/3)x + 30 Y = (-2/3)x + 30 20 When the laser beam is shined at the ground at 30 ft. up it will hit the ground at 45 ft. from the face of the building using the equation Y=(-2/3)x + 30. 15 10 (30, 10) 5 X Axis 0 0 Y Axis 10 20 30 The height of the beam 30 ft. away from the face of the building is 10 ft. X intercept (45, 0) 40 50 X represents the distance from face of bldg. in ft. The laser beam hits the side of the building at 30 ft. which is the Y intercept (0, 30) and the laser beam hits the ground at 45 ft. from the face of the building at the X intercept (45, 0). X intercept (45, 0). ...

Words: 274 - Pages: 2

Free Essay

...Task 1 1. Graph the points (1,0,-6,3/4,1.7) in single number line. 2. Graph the following points on a single coordinate plane. Make sure to include labels for each quadrant of the coordinate plane. • Point 1: (3, –2) • Point 2: (0, 0) • Point 3: (–1, 7) • Point 4: (3, 5) • Point 5: (–4, –5) 3. Graph the following functions on separate coordinate planes. Function 1: y= 2x − 1 If x = 0 y= 2x − 1 y= 2(0) − 1 y= − 1 If x = 1 y= 2x − 1 y= 2(1) − 1 y= 2 − 1 y= 1 If x = 2 y= 2x − 1 y= 2(2) − 1 y= 4 − 1 y= 3 If x = 3 y= 2x − 1 y= 2(3) − 1 y= 6 − 1 y= 5 If x = 4 y= 2x − 1 y= 2(4) − 1 y= 8 − 1 y= 7 Function 2: y= (–3/4)x+ 5 If x = 0 y= (–3/4)x+ 5 y= (–3/4)(0)+ 5 y= 5 If x = 1 y= (–3/4)x+ 5 y= (–3/4)(1)+ 5 y= –3/4 + 5 y= 4 1/4 If x = 2 y= (–3/4)x+ 5 y= (–3/4)(2)+ 5 y= –1 1/2 + 5 y= 3 1/2 If x = 3 y= (–3/4)x+ 5 y= (–3/4)(3)+ 5 y= –2 1/4 + 5 y= 2 3/4 If x = 4 y= (–3/4)x+ 5 y= (–3/4)(4)+ 5 y= –3 + 5 y= 2 Function 3: y= x2 – 4 If x = 0 y= x2 – 4 y= (0)2 – 4 y= -4 If x = 1 y= x2 – 4 y= (1)2 – 4 y= 1 – 4 y= -3 If x = 2 y= x2 – 4 y= (2)2 – 4 y= 4 – 4 y= 0 If x = 3 y= x2 – 4 y= (3)2 – 4 y= 9 – 4 y= 5 If x = 4 y= x2 – 4 y= (4)2 – 4 y= 16 – 4 y= 12 Function 4: y= –3x2 − 6x – 5 If x =...

Words: 458 - Pages: 2

Free Essay

...000278346/Arpe/QLT1 Task 212.1.2: Task 1 A. Complete the following graphs: 1. Graph the following values on a single number line. Value 1: 1 Value 2: 0 Value 3: -6 Value 4: ¾ Value 5: -1.7 B C E D A Page 1 of 6 000278346/Arpe/QLT1 Task 212.1.2: Task 1 2. Graph the following points on a single coordinate plane. Make sure to include labels for each quadrant of the coordinate plane. Point 1: (3,-2) Point 2: (0.0) Point 3: (-1,7) Point 4: (3,5) Point 5: (-4,-5) (-1,7) (3,5) (3,-2) ) (0,0) (3,-2) (-4,-5) Page 2 of 6 000278346/Arpe/QLT1 Task 212.1.2: Task 1 3. Graph the following functions on separate coordinate planes. In each graph, label each axis of the coordinate plane. Additionally, label each intercept as “x-intercept” or “y-intercept” and include the ordered pair. Whenever applicable, label the vertex as “vertex” and include the ordered pair Function 1: y = 2x – 1 (3,5) (2,3) ( ½ ,0) (0,-1) x-intercept y-intercept (-1,-3) Page 3 of 6 000278346/Arpe/QLT1 Task 212.1.2: Task 1 Function 2: y = (-3/4)x + 5 (-4,8) x-intercept (0,5) (4,2) y-intercept (6 ½,0) (8,-1)) Page 4 of 6 000278346/Arpe/QLT1 Task 212.1.2: Task 1 Function 3: y = x2 – 4 (-3,5) (3,5) (-2,0) x-intercept (2,0) x-intercept (-1,-3) (1,-3) (0,-4) Vertex Page 5 of 6 000278346/Arpe/QLT1 Task 212.1.2: Task 1 Function 4: y = -3x2 – 6x –......

Words: 295 - Pages: 2

Free Essay

...A1) A parent is looking for the best option for daycare for a child. A home-based option charges a flat rate of $10 per hour. A center-based option charges a fixed fee of $332.50 per week for 35 hours and then a fixed rate of $11 per hour for any hour provided over the set amount. Determine which option is most advantageous for the parent based upon the parents’ needs. A2) The parent works a 40 hour work week. Each of the daycare options is a half an hour away from the parent’s office. This means that the child is there for a total of 45 hours a week. The parent has federal holidays (10 holidays in 2014), the day after Thanksgiving, and Christmas Eve off so there will be weeks that the child will not be in daycare for the full week. The parent also receives two weeks of vacation each year. Other situations to consider are that the child and/or parent could get sick or they could take a short vacation and the child will not have to attend the daycare for the full week. A3) If the parent chooses to go with the home-based option, the parent will be charged a flat rate of $10 per hour. This option gives the parent the freedom to either take the child to daycare or to not and only be charged for the hours the child is there. If the child is there for 45 hours a week, the parent will pay $450 for that week; if the child is there for only 20 hours a week, the parent will pay $200 for that week. If the parent chooses to go with the center-based option, the parent will be charged......

Words: 837 - Pages: 4

Premium Essay

...QLT1 Task 5 Daycare Cost Analysis A.) Basic information: The Depp family is seeking child care for their 2 year old son Jack. The family needs care for approximately 42-50 hours per week. They have interviewed several care providers and have selected two providers in the vicinity of their employers and now need to decide between: one is family day care home that charges $5 per hour per child and the other is a child care center that charges $200 per week for 40 hours with an additional $10 per hour over 40 hours. Additional factors considered are that both facilities provide lunch and snacks, other facilities did not; as well the center will provide a 25% discount on a second child. Although the Depps have only one child however will be adding to their young family. 1.) Rates: i. Daycare rates: Home care $5/hour ii. Center $200/week for 40 hours + $10/hour over 40 hours 2.) Other expenses iii. Meals included with both facilities iv. Both located within 10 blocks of employer, transportation costs are negligible 3.) Other considerations v. Parents are state employees 37.5 hours per week + 1 hour lunch = 42.5 hours @ employer per week minimum vi. Currently have one child in need of care, but is considering another child in the next 1-2 years vii. Family day care home is 1 employee, no coverage for sick days/vacation; center has multiple staff members to......

Words: 456 - Pages: 2

Free Essay

...QLT1 – Task 1 Competency 212.1.2: Solving Algebraic Equations A. 1. Graph the following values on a single number line • Value1: 1 • Value 2: 0 • Value 3: -6 • Value 4: ¾ • Value 5: -1.7 [pic] 2. Graph the following points on a single coordinate plane. Make sure to include labels for each quadrant of the coordinate plane. • Point 1: (3,-2) • Point 2: (0,0) • Point 3: (-1,7) • Point 4: (3,5) • Point 5: (-4,-5) Quadrant II Quadrant I [pic] Quadrant III Quadrant IV 3. Graph the following functions on separate coordinate planes. • Function 1: y= 2x − 1 y=2(0) – 1 0=2x – 1 y= 0 – 1 +1 +1 y= -1 1 = 2x /2 /2 ½ = x [pic] • Function 2: y= (–3/4)x + 5 y=(-3/4)0 + 5 0=(-3/4)x + 5 y= 0 + 5 -5 -5 y = 5 (0,5) -5 = (-3/4)x *4 *4 -20 = -3x /-3 /-3 6.67 = x (6.67,0) [pic] • Function 3: y=x2 – 4 y=02 – 4 0=x2 – 4 y=(-2) 2 – 4 y=(3)2 -4 y=(-3)2-4 y=-4 +4 +4 y = 4 – 4 y=9-4 y=9-4 4= x2 y = 0 y = 5 y = 5 √4 = √x2 2 = x [pic] • Function 4: y= –3x2 – 6x – 5 If x=0 then If x=-1 then y= –3(0)2 – 6(0) – 5 y= –3(-1)2 – 6(-1) – 5 y = 0 – 0 – 5......

Words: 424 - Pages: 2

Premium Essay

...QLT 1: Task 5 A1. Ryan has started a new job in downtown Atlanta. He is looking at different options for parking his vehicle during the workweek. He has narrowed it down to two options, a parking garage offering a flat rate of $30 dollars a month and another garage slightly further away which charges 0.15¢ per hour. A2. Ryan just recently moved to Atlanta for this new job opportunity. Taking into consideration the financial impact the move has created such as purchasing a new place, new furniture, and all necessary necessities, it will be critical he find the cheapest option for parking. A3. The first cost option is parking garage A, which features a monthly unlimited parking pass for $30 dollars a month. The second option is parking garage B, which is slightly further away from his job but charges 0.15¢ a hour. B1. To determine the best cost effective parking option we will need to determine which offers the best rates. A standard 8 hour work day will be used to determine how many hours per day to charge. a = Number of days, x = Total price. Parking garage A - (a - a) + 30 = x Parking garage B - (0.15 x 8) a = x B2. Parking Garage A will be charged a flat rate regardless of how many days it is used. Thus having the days cancel out so the flat 30 dollars is consistent across the month is needed to compare the relationship of parking garage B. Parking Garage B since it is a hourly rate will need to take into account the standard work......

Words: 673 - Pages: 3

Free Essay

...A. 1. A. 2. Savings Plan A y= $20x + $400 10x+600=20x+400 -10x-400=-10x -400 200=10x /10 /10 20=x (# 0f months) Savings PlanB y= $10x + $600 y=10(20)+600 y=200+600 y=800 ($ saved) Savings Plan A X-intercept y=0 0=20x+400 -400=20x -400/20=x -20=X Savings PlanB X-intercept y=0 0=10x+600 -600=10x -600/10=x -60=x Solution A. 3. Both plans yield identical balances after 20 months at $800. Months Plan B Plan A -60 0 -20 0 0 600 0 400 2 620 2 440 Solution 3 630 3 460 1000 4 640 4 480 (20,800) y-intercept Quadrant II 5 650 5 500 800 (0,600) 6 660 6 520 600 Quadrant I 7 670 7 540 400 8 680 8 560 x-intercept (0,400) y-intercept x-intercept 200 9 690 9 580 (-60,0) (-20,0) 10 700 10 600 0 -70 -60 -50 -40 -30 -20 -10 0 10 20 30 11 710 11 620 X-Axis Months 12 720 12 640 13 730 13 660 Plan B y=10x+600 Plan A y=20x+400 14 740 14 680 Linear (Plan B y=10x+600) Linear (Plan A y=20x+400) 15 750 15 700 16 760 16 720 17 770 17 740 A.3a1. Plan B yields more at $740 vs. Plan A at $680. 18 780 18 760 A.3ac. Plan A yields more at $860 vs Plan B at $830. 19 790 19 780 A.4. The solution lies in quadrant 1 where the savings 20 800 20 800 begins until the intersection at (20,800). 21 810 21 820 x & y coordinates are all positive from month 1 through month 20 22 820 22 840 which means its Quadrant 1. 23 830 23 860 Y-Axis (Total Savings in $) ...

Words: 320 - Pages: 2

Premium Essay

...A1 Andrew has just moved to Los Angeles and bought a car and is looking for the best parking option that will allow him to save the most money. There are two parking garages by his work. One charges $40 per month and the other charges 20 cents per hour. Which option will be less costly for him? A2 Since Andrew is new to the area it is necessary that he find the cheapest parking option possible in order to cut down on expenses in the new city as he has just purchased a new car and had high moving costs. A3 Andrew’s two options are the monthly parking garage which charges $40 per month or the hourly parking garage which charges 20 cents per hour. B1 A work day has 8 hours A is the number of days the car will be parked. T will be the total price Monthly parking garage: (A-A)+40=T Hourly parking garage: (0.2 x 8)A=T B2 The monthly parking garage doesn’t charge by the day so having the days at zero just leaves the $40 charge. The hourly parking garage multiplies the rate by 8 hours since there are 8 hours in a work day. That is then multiplied by the total number of days in a month that the car will be parked. B3 We set both equations equal to each other in order to find the solution for the number of days. Set both equations equal to each other (A-A)+40=(0.2 x 8)A Subtract (A-A) 40=(0.2 x 8)A Multiply inside the parentheses (0.2 x 8) 40=(1.6)A Multiply (1.6)A 40=1.6A Divide both sides by 1.6 25=A A=25 days solution We...

Words: 501 - Pages: 3

Premium Essay

...SUBDOMAIN 212.1 - NUMERACY, ALGEBRA, & GEOMETRY SUBDOMAIN 212.2 - PROBABILITY, STATISTICS, & QUANTITATIVE PROBLEM SOLVING Competency 212.1.2: Solving Algebraic Equations - The graduate solves algebraic equations and constructs equations to solve real-world problems. Competency 212.2.1: Applying Probability and Statistics - The graduate understands and applies elementary probability and statistics concepts and knows the relationship between them and sampling and inference. Competency 212.2.3: Interpreting and Communicating Quantitative Information - The graduate interprets documents and materials containing quantitative information and effectively communicates mathematical arguments and quantitative results. Competency 212.2.4: Applying Technology to Quantitative Problems - The graduate uses appropriate technological tools, including regular and graphing calculators, databases, and/or statistical analysis programs, to solve problems involving computation, graphical information, and informational technology in a wide range of areas. Introduction: Individuals encounter countless situations in day-to-day life that require a strong mathematical foundation in order to make informed decisions. Shown below are four real-world scenarios that one might encounter in day-to-day life. For this task you will choose one of the scenarios below. Each situation requires a mathematical comparison of cost options in order to determine which is best for a consumer (e.g., customer or person).......

Words: 1020 - Pages: 5

Premium Essay

...Task 5 A. Jenny is looking for the best option for daycare for her son. She lives in a small town, so her options are limited to two daycare centers. Option A is a home-based facility which charges $9.00 per hour that the child is at the home. Option B is a center-based facility which charges $150 for the first 20 hours and then charges $10 per hour thereafter. Due to a new promotion, Jenny will be required to work more hours away from home. Which facility will cost less for Jenny to have her son in daycare for a work week (40 hours)? B. I. h = how many hours of child care is needed = 40 f = the flat hourly rate charge t = total amount due for the week Option A: f * h = t a. 9 * 40 = $360 Option B: 150 + f(h-20) = t, for h >=20 b. 150 + 10(40-20) = $350 150 = t, for h < 20 c. 150 = total II. I set the hours to "h", the hourly fee to "f" and the total to "t". a. Option A: This option only has an hourly fee for each hour. The fee is $9 and the amount of hours is 40 so I multiplied the hours by the fee. b. Option B: This option has a flat rate of $150 for the first 20 hours and then an hourly rate of $10 thereafter. For the first equation that refers to over 20 hours, I subtracted 20 hours from the total time, multiplied it by $10, and then added it to $150. For the second equation that refers to any amount less than 20 hours, the total is always......

Words: 531 - Pages: 3

Premium Essay

...Task 5 Moving Truck Cost Analysis The Thompsons have lived in Canada all their life but recently Mr. Thompson got a job offer he could not refuse. The new job will require they move to the west coast of the United States. This is going to require they move across the country from New Brunswick, Canada to Seattle, WA. Which is a total of 3200 miles. Although the company Mr. Thompson will be working for will reimburse them for the move, they still have a budget they need to stay under so they can have enough money for hotel stays, stocking the house with food, cleaning supplies etc. when they arrive. They are planning on leaving early and site seeing on the way but still arrive at least two weeks early so they have time to settle in. Arriving early though means there will be a big gap between paychecks so budgeting is very important. They narrowed it down to two companies, Acme Moving which charges $2.00 per mile and Lightening Moving that charges $1500 for the first thousand miles and $2.25 for each mile over 1000. They have to analyze the costs and figure out which one is going to be the best deal. The Equation: Lightening Moving Co. Lightening Moving charges $1500 for the first 1000 miles and then $2.25 for each mile over 1000. Let X = Amount of miles traveled 1500 = the initial cost of the first 1000 miles 3,200 = the total amount of miles traveled $2.25 per mile over 1000 miles therefore; 1500 + 2.25(X-1000) = Cost of moving over 1000 miles 1500 + 2...

Words: 550 - Pages: 3